Democratic Underground Latest Greatest Lobby Journals Search Options Help Login
Google

ok all you smarty smarts...answer this simple math/geometry question

Printer-friendly format Printer-friendly format
Printer-friendly format Email this thread to a friend
Printer-friendly format Bookmark this thread
This topic is archived.
Home » Discuss » The DU Lounge Donate to DU
 
pokerfan Donating Member (1000+ posts) Send PM | Profile | Ignore Tue Apr-24-07 07:39 PM
Original message
ok all you smarty smarts...answer this simple math/geometry question
One of my personal favorite puzzles. No fair googling.

Two ladders of lengths a = 40 and b = 30 feet are propped in an alley, as shown. The ladders cross each other at a height of h = 12 feet above the alley floor. What is the width of the alley?



Printer Friendly | Permalink |  | Top
mainegreen Donating Member (1000+ posts) Send PM | Profile | Ignore Tue Apr-24-07 07:47 PM
Response to Original message
1. I hate you.
Now I have to work on this.
x(
Printer Friendly | Permalink |  | Top
 
pokerfan Donating Member (1000+ posts) Send PM | Profile | Ignore Tue Apr-24-07 10:35 PM
Response to Reply #1
4. Bumping for the math geeks
Printer Friendly | Permalink |  | Top
 
pintobean Donating Member (1000+ posts) Send PM | Profile | Ignore Tue Apr-24-07 07:52 PM
Response to Original message
2. I believe this is
an OSHA violation. The proper lean ratio is 4 to 1. Not only that, it's out of focus.
Printer Friendly | Permalink |  | Top
 
pokerfan Donating Member (1000+ posts) Send PM | Profile | Ignore Tue Apr-24-07 07:58 PM
Response to Reply #2
3. LOL
Printer Friendly | Permalink |  | Top
 
Redstone Donating Member (1000+ posts) Send PM | Profile | Ignore Tue Apr-24-07 10:36 PM
Response to Original message
5. Just wide enough to have another drink in.
Redstone
Printer Friendly | Permalink |  | Top
 
hellbound-liberal Donating Member (1000+ posts) Send PM | Profile | Ignore Wed Apr-25-07 05:58 AM
Response to Original message
6. You're going to have to give me some time to think about this
Please don't post the answer before 5:00 PM today. I'll have my answer by then. Maybe.
Printer Friendly | Permalink |  | Top
 
meegbear Donating Member (1000+ posts) Send PM | Profile | Ignore Wed Apr-25-07 06:33 AM
Response to Original message
7. ...






































21 feet
Printer Friendly | Permalink |  | Top
 
pokerfan Donating Member (1000+ posts) Send PM | Profile | Ignore Wed Apr-25-07 07:15 AM
Response to Reply #7
8. Nope
It's not an integer.

Printer Friendly | Permalink |  | Top
 
commander bunnypants Donating Member (1000+ posts) Send PM | Profile | Ignore Wed Apr-25-07 07:41 AM
Response to Original message
9. 47
CB
Printer Friendly | Permalink |  | Top
 
wildhorses Donating Member (1000+ posts) Send PM | Profile | Ignore Wed Apr-25-07 08:30 AM
Response to Original message
10. the answer is 42
always;)
Printer Friendly | Permalink |  | Top
 
commander bunnypants Donating Member (1000+ posts) Send PM | Profile | Ignore Wed Apr-25-07 08:43 AM
Response to Reply #10
11. I thought it was 47
danks

CB
Printer Friendly | Permalink |  | Top
 
wildhorses Donating Member (1000+ posts) Send PM | Profile | Ignore Wed Apr-25-07 08:46 AM
Response to Reply #11
12. of course 69 is always a good solution --
:evilgrin:

:hi:
Printer Friendly | Permalink |  | Top
 
hellbound-liberal Donating Member (1000+ posts) Send PM | Profile | Ignore Wed Apr-25-07 06:42 PM
Response to Original message
13. I give up, Pokerfan. Is this figure drawn to scale?
Printer Friendly | Permalink |  | Top
 
pokerfan Donating Member (1000+ posts) Send PM | Profile | Ignore Wed Apr-25-07 07:31 PM
Response to Reply #13
14. Not drawn to scale, but the answer is
there is no answer. Well, of course there is an "answer," but it can not be solved directly.

It looks like it should be relatively easy but devolves into algebraic hell:

B^4-2hB^3+B^2(a^2-b^2)-2hB(a^2-b^2)+c^2(a^2-b^2)=0

Solving a 4th degree equation is a little difficult. But if you can solve the above equation for B, then you can easily deduce w using the Pythagorean Theorem.

Wikipedia has a pretty good entry on the problem: http://en.wikipedia.org/wiki/Crossed_Ladders_Problem

I like to spring it on engineering candidates just to torture them and get some insight on how they go about the problem solving process.

Printer Friendly | Permalink |  | Top
 
MikeH Donating Member (1000+ posts) Send PM | Profile | Ignore Mon Apr-30-07 01:09 AM
Response to Reply #14
16. B = very close to 19, w = a little over 23.2 feet
I was trying this out.

For a = 40, b = 30, h = 12, the above formula works to

B^4 - 24*B^3 + 700*B^2 - 16800*B + 100800 = 0

which can also be written (for ease of calculation) as

(((B-24)B+700)B-16800)B+100800

Looking at the geometry, one would see that B > 12 (h) and B < 30 (b).

It turns out that B=19 gives the value 5 for the above expression, which is very, very close given the large coefficients and large values of the powers; the true value of B is just very, very slightly less than 19.

This gives w = approximately the square root of 900 - 361 = 539, or slightly over 23.2 feet.
Printer Friendly | Permalink |  | Top
 
Rabrrrrrr Donating Member (1000+ posts) Send PM | Profile | Ignore Wed Apr-25-07 07:37 PM
Response to Original message
15. The answer depends on A and B - I'd give you a complex formula,
but quite honestly I don't feel like doing that.

But I do know that, given the data you've given, the answer can only be expressed in terms of A and B, and it'll be a big, beautiful (ugly to non-math-geeks, but they don't count as human beings, so I ignore them) equation.
Printer Friendly | Permalink |  | Top
 
KitchenWitch Donating Member (1000+ posts) Send PM | Profile | Ignore Mon Apr-30-07 01:12 AM
Response to Original message
17. Oh sweet zombie jesus - you are evil!
x(
Printer Friendly | Permalink |  | Top
 
DU AdBot (1000+ posts) Click to send private message to this author Click to view 
this author's profile Click to add 
this author to your buddy list Click to add 
this author to your Ignore list Fri May 03rd 2024, 07:57 PM
Response to Original message
Advertisements [?]
 Top

Home » Discuss » The DU Lounge Donate to DU

Powered by DCForum+ Version 1.1 Copyright 1997-2002 DCScripts.com
Software has been extensively modified by the DU administrators


Important Notices: By participating on this discussion board, visitors agree to abide by the rules outlined on our Rules page. Messages posted on the Democratic Underground Discussion Forums are the opinions of the individuals who post them, and do not necessarily represent the opinions of Democratic Underground, LLC.

Home  |  Discussion Forums  |  Journals |  Store  |  Donate

About DU  |  Contact Us  |  Privacy Policy

Got a message for Democratic Underground? Click here to send us a message.

© 2001 - 2011 Democratic Underground, LLC