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Wed Jan 4, 2023, 01:51 PM

Doesn't this further splitting of the R votes give the D's a chance to get Jeffries in?

If they do they math right, the last 6 or so Dems could not vote and Jeffries would have the majority.

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Reply Doesn't this further splitting of the R votes give the D's a chance to get Jeffries in? (Original post)
Cuthbert Allgood Jan 4 OP
SCantiGOP Jan 4 #1
Cuthbert Allgood Jan 4 #7
SCantiGOP Jan 4 #21
Cattledog Jan 4 #2
Cuthbert Allgood Jan 4 #8
Trumpdumper Jan 4 #3
Cuthbert Allgood Jan 4 #9
tritsofme Jan 4 #14
Cuthbert Allgood Jan 4 #15
tritsofme Jan 4 #18
ZonkerHarris Jan 4 #4
Cuthbert Allgood Jan 4 #10
LiberalFighter Jan 4 #5
RockRaven Jan 4 #6
Cuthbert Allgood Jan 4 #11
Orangepeel Jan 4 #12
Cuthbert Allgood Jan 4 #13
RockRaven Jan 4 #20
wryter2000 Jan 4 #16
Cuthbert Allgood Jan 4 #17
onenote Jan 4 #19
Emile Jan 4 #22

Response to Cuthbert Allgood (Original post)

Wed Jan 4, 2023, 01:55 PM

1. I heard this discussed

If they could pull that off, then the Republican majority would have to vote for the rules, in which case they would allow his removal.

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Response to SCantiGOP (Reply #1)

Wed Jan 4, 2023, 02:03 PM

7. So then they need to do that, I guess.

Just further evidence of their clown show.

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Response to Cuthbert Allgood (Reply #7)

Wed Jan 4, 2023, 04:53 PM

21. I don't disagree

but I think their current strategy of just sitting back and letting them act like an ungovernable band of idiots is paying dividends.

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Response to Cuthbert Allgood (Original post)

Wed Jan 4, 2023, 01:56 PM

2. He'd need 218 votes for a majority in the House.

Possible with less but highly unlikely.

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Response to Cattledog (Reply #2)

Wed Jan 4, 2023, 02:03 PM

8. Not if people don't vote.

He needs the majority of the votes cast.

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Response to Cuthbert Allgood (Original post)

Wed Jan 4, 2023, 01:57 PM

3. You'd need R's not to vote to decrease the denominator in the right way. The D's all need to vote.

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Response to Trumpdumper (Reply #3)

Wed Jan 4, 2023, 02:04 PM

9. Not true.

You just have to do the math right so that Jeffries gets the majority. It wasn't possible with yesterday's votes, but with them further splitting, the math is doable.

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Response to Cuthbert Allgood (Reply #9)

Wed Jan 4, 2023, 02:13 PM

14. The math is the same, there are still 212 Democratic votes

It would still take 12 Republicans to vote present, regardless of how they split, for 212 to make a majority.

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Response to tritsofme (Reply #14)

Wed Jan 4, 2023, 02:19 PM

15. The votes for McCarthy was only split with Donalds. Had it been split more

than the D's could bring the amount down to get the majority.

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Response to Cuthbert Allgood (Reply #15)

Wed Jan 4, 2023, 02:23 PM

18. It doesn't matter if Republicans split down the middle, the math doesn't change.

It still would take 12 Republicans either not showing up or voting present for Jeffries’ 212 votes to constitute a majority.

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Response to Cuthbert Allgood (Original post)

Wed Jan 4, 2023, 01:58 PM

4. 218 to win. We do not have 218 in any way shape or form.

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Response to ZonkerHarris (Reply #4)

Wed Jan 4, 2023, 02:04 PM

10. Majority of votes cast to win. Not 218.

That's why the Rs were asking if some Ds would not vote to give McCarthy the win yesterday.

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Response to Cuthbert Allgood (Original post)

Wed Jan 4, 2023, 01:58 PM

5. All Dems would need to vote for Jeffries. It would require some R's voting Present.

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Response to Cuthbert Allgood (Original post)

Wed Jan 4, 2023, 01:59 PM

6. Nope. Think about the math for a second. A vote for Jeffries adds one to the numerator and

the denominator. That always moves his needle up, no matter how the other votes have been split, and his needle needs to get over 50%.

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Response to RockRaven (Reply #6)

Wed Jan 4, 2023, 02:05 PM

11. He needs the majority of the votes cast, not a hard 218.

The math is doable if McCarthy is losing like 50 R votes to other people.

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Response to Cuthbert Allgood (Reply #11)

Wed Jan 4, 2023, 02:09 PM

12. He'd need the Rs not to vote. Voting for other people doesn't help

the Rs not voting for McCarthy want to cause chaos. They don't want to help the Democrats.

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Response to Orangepeel (Reply #12)

Wed Jan 4, 2023, 02:10 PM

13. I get that's what they want, but if my math is correct, we would need 20 no votes

to give Jeffries the majority. Now, I fully realize that the R's should understand that is what they are doing when the 20th to the last D voted present, but they have shown to be stupid.

But the math and the rules work.

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Response to Cuthbert Allgood (Reply #11)

Wed Jan 4, 2023, 02:42 PM

20. The OP asked about *Democrats* abstaining from voting, that is what my answer addresses.

And nowhere did I cite any specific vote number.

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Response to Cuthbert Allgood (Original post)

Wed Jan 4, 2023, 02:20 PM

16. If a Dem doesn't vote

You lose half a number in the denominator, but you lose a whole number in the numerator. Any Dem not voting is a loss for Jeffries.

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Response to Cuthbert Allgood (Original post)

Wed Jan 4, 2023, 02:22 PM

17. UPDATE ON THE MATH: Only Donalds got votes, so it won't work

But if 20 people voted for Donalds and 20 people voted for Jordan, it becomes very possible for Dems voting present to get Jeffries the majority. Seems like the R's aren't as stupid as they seem.

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Response to Cuthbert Allgood (Reply #17)

Wed Jan 4, 2023, 02:30 PM

19. Pretty sure the same people who voted for Donalds

Voted for Jordan. There aren’t 40 repubs who voted vs McCarthy

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Response to Cuthbert Allgood (Original post)

Wed Jan 4, 2023, 04:56 PM

22. Only if McCarthy voters get pissed and throw

enough votes to Jefferies and that ain't gonna happen.

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